`bbu = ` Find a unit vector in the direction of the given vector. Verify that the result has a magnitude of 1.

Hence, you need to find the unit vector having the same direction as the vector `v = <0,-2>` , hence, you need to use the formula, such that:

`u = v/|v|`

You need to evaluate the magnitude |v|, such that:

`|v| = sqrt(a^2+b^2)`

`|v| = sqrt(0^2 + (-2)^2) => |v| = sqrt(0+4) => |v| = sqrt 4 => |v| = 2`

`u = (<0,-2>)/2=> u = <0/2, -2/2>`

`u = <0, -1>`

You need to check that the magnitude of the unit vector is 1, such that:

`|u| = sqrt(0^2 + (-1)^2)`

`|u| = sqrt(0+1)`

`|u| = sqrt (1)`

`|u| = 1`

Hence, evaluated the unit vector yields `u = <0, -1>.`