We have to find the first term `a_1` and the common difference `d,` then the general formula will be `a_n=a_1+(n-1)d.`
The difference between `a_6` and `a_3` is equal to 3 common differences, i.e.
`d=(a_6-a_3)/3=(85-94)/3=-9/3=-3.`
The first term is 2 common differences less than 3-rd, so
`a_1=a_3-2d=94+2*3=100.`
So the answer is: `a_n=100-(n-1)*3.`
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