3.46 moles of C3H8 are burned in a room with excess oxygen gas. How many moles of carbon dioxide are released into the atmosphere during this...

The balanced chemical reaction for this reaction is given as:

`C_3H_8 + 5O_2 -> 3CO_2 + 4H_2O`

When propane (C3H8) is burned in the presence of excess oxygen, carbon dioxide and water are generated. Using stoichiometry, 1 mole of butane reacts with 5 moles of oxygen and generates 3 moles of carbon dioxide and 4 moles of water.

In the given case, 3.46 moles of butane undergo combustion. Since, 1 mole butane generates 3 moles of carbon dioxide, 3.46 moles will generate 10.38 moles (= 3 x 3.46) of carbon dioxide. 

Since, the molecular mass of carbon dioxide is 44 gm/mole (= 12 + 2 x 16), the amount of carbon dioxide generated is 456.72 gm (= 10.38 moles x 44 gm/mole).

We can also calculate the amount of water generated in this reaction. 3.46 moles of butane, on combustion, generates 13.84 moles of water. 

Hope this helps.