Given `a=3.05, b=0.75, c=2.45`
Heron's Area Formula `A=sqrt[s(s-a)(s-b)(s-c)]`
where `s=(a+b+c)/2`
`s=(3.05+0.75+2.45)/2=6.25/2=3.125`
`A=sqrt[(3.125)(3.125-3.05)(3.125-0.75)(3.125-2.45)]`
`A=sqrt[(3.125)(.075)(2.375)(.675)]`
`A=0.6129`
The area is 0.6129 squared units.
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