Friday, December 24, 2010

`bbw = 4bbj` Find a unit vector in the direction of the given vector. Verify that the result has a magnitude of 1.

Hence, you need to find the unit vector having the same direction as the vector `w = 4j => w = <0,4>` , hence, you need to use the formula, such that:


`u = w/|w|`


You need to evaluate the magnitude |w|, such that:


`|w| = sqrt(a^2+b^2)`


`|w| = sqrt(0^2 + 4^2) => |w| = sqrt(0+16) => |w| = sqrt16 => |w| = 4`


`u = ( <0,4>)/4=> u = <0/4, 4/4>`


`u = <0,1>`


You need to check that the magnitude of the unit vector is 1, such that:


`|u| = sqrt(0^2 + 1^2)`


`|u| = sqrt (1)`


`|u| = 1`


Hence, evaluating the unit vector yields` u = <0,1>.`

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