`v = ` Find a unit vector in the direction of the given vector. Verify that the result has a magnitude of 1.

Hence, you need to find the unit vector having the same direction as the vector `v = <3,0>` , hence, you need to use the formula, such that:

`u = v/|v|`

You need to evaluate the magnitude |v|, such that:

`|v| = sqrt(a^2+b^2)`

`|v| = sqrt(3^2 + (0)^2) => |v| = sqrt(9+0) => |v| = sqrt 9 => |v| = 3`

`u = (<3,0>)/3=> u = <3/3, 0/3>`

`u = <1,0>`

You need to check that the magnitude of the unit vector is 1, such that:

`|u| = sqrt(1^2 + 0^2)`

`|u| = sqrt(1+0)`

`|u| = sqrt (1)`

`|u| = 1`

Hence, evaluating the unit vector yields `u = <1,0>.`