`bbv = ` Find a unit vector in the direction of the given vector. Verify that the result has a magnitude of 1.

Hence, you need to find the unit vector having the same direction as the vector `v = <5,-12>` , hence, you need to use the formula, such that:

`u = v/|v|`

You need to evaluate the magnitude |v|, such that:

`|v| = sqrt(a^2+b^2)`

`|v| = sqrt(5^2 + (-12)^2) => |v| = sqrt(25+144) => |v| = sqrt 169 => |v| = 13`

`u = (<5,-12>)/13 => u = <5/13, -12/13>`

You need to check that the magnitude of the unit vector is 1, such that:

`|u| = sqrt((5/13)^2 + (-12/13)^2)`

`|u| = sqrt(25/169 + 144/169)`

`|u| = sqrt ((25+144)/169)`

`|u| = sqrt (169/169)`

`|u| = sqrt 1`

`|u| = 1`

Hence, evaluated the unit vector yields `u = <5/13, -12/13>.`