`||bbv|| = 10, bbu = ` Find the vector `bbv` with the given magnitude and the same direction as `bbu`.

The magnitude of a vector `v=v_x*i + v_y*j` is given by the following formula, such that:

`|v| = sqrt(v_x^2+v_y^2)`

The problem provides the information that |v| = 10:

`10 = sqrt(v_x^2+v_y^2)`

You may evaluate the direction angle of the vector v, such that:

`tan alpha = (v_y)/(v_x)`

The problem provides the information that the direction angle of the vector v coincides to the direction angle of the vector `u = <-3,4>` .

`tan alpha = -4/3`

`(v_y)/(v_x) = -4/3 => v_y = (-4/3 )*(v_x)`

Replacing `(-4/3 )*(v_x)` for `v_y ` yields:

`10 = sqrt(v_x^2+(16/9)*(v_x^2))`

`10 = +-(5/3)*(v_x)`

`2 = +-(1/3)*(v_x) => v_x = +-6 => v_y = +-8`

Hence, evaluating the vector v yields `v = 6i - 8j` or `v = -6i + 8j.`