Given: `A=100^@, a=125, c=10`
The Law of Sines: `a/sin(A)=b/sin(B)=c/sin(C)`
`125/sin(100)=b/sin(B)=10/sin(C)`
`sin(C)=[10sin(100)]/125`
`sin(C)=.0788`
`C=arcsin(.0788)`
`C=4.52^@`
`B=180-100-4.52`
`B=75.48^@`
`125/sin(100)=b/sin(75.48)`
`b=[125sin(75.48)]/sin(100)`
`b=122.87`
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