`bbv = ` Find a unit vector in the direction of the given vector. Verify that the result has a magnitude of 1.

Hence, you need to find the unit vector having the same direction as the vector `v = <-2,2>` , hence, you need to use the formula, such that:

`u = v/|v|`

You need to evaluate the magnitude |v|, such that:

`|v| = sqrt(a^2+b^2)`

`|v| = sqrt((-2)^2 + 2^2) => |v| = sqrt(4+4) => |v| = sqrt 8 => |v| = 2sqrt2`

`u = (<-2,2>)/(2sqrt2) => u = <-2/(2sqrt2), 2/(2sqrt2)>`

`u = <-1/(sqrt2), 1/(sqrt2)>`

You need to check that the magnitude of the unit vector is 1, such that:

`|u| = sqrt((-1/(sqrt2))^2 + (1/(sqrt2))^2)`

`|u| = sqrt(1/2 + 1/2)`

`|u| = sqrt (1)`

`|u| = 1`

Hence, evaluated the unit vector yields `u = <-1/(sqrt2), 1/(sqrt2)>.`