The magnitude of a vector `u = a*i + b*j,` such that:
`|u| = sqrt(a^2+b^2)`
Since the problem provides the magnitude `|v| = 3` , yields:
`3 = sqrt(a^2+b^2)`
The direction angle of the vector can be found using the formula, such that:
`tan theta = b/a`
Since the problem provides the direction angle `theta = 0^o` , yields:
`tan 0^o = b/a => b/a = 0 => b = 0, a!=0`
Replacing 0 for b in equation `3 = sqrt(a^2+b^2)` yields:
`3 = sqrt(a^2+0^2) => 9 = a^2 => a = +-3`
Hence, the component form of the vector v can be `<-3,0>` or` <3,0>.`
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