`A = 110^@, a = 125, b = 100` Use the law of sines to solve (if possible) the triangle. If two solutions exist, find both. Round your answer...

Given: `A=110^@, a=125, b=100`

The Law of Sines:  `a/sin(A)=b/sin(B)=c/sin(C)`

`125/sin(110)=100/sin(B)=c/sin(C)`

`125/sin(110)=100/sin(B)`

`sin(B)=[100sin(110)]/125`

`sin(B)=.7518`

`B=arcsin(.7518)`

`B=48.74^@`

`C=180-110-48.74`

` C=21.26^@`

`125/sin(110)=c/sin(21.26)`

`c=[125sin(21.26)]/sin(110)`

`c=48.23`