How many grams of carbon dioxide would be required to form 332.31 grams of glucose, assuming abundant water was available?

The chemical reaction that converts carbon dioxide and water to glucose can be written as:

`6CO_2 + 6H_2O -> C_6H_12O_6 + 6O_2`

Here, 6 moles of carbon dioxide reacts with 6 moles of water and forms 1 mole o glucose and 6 moles of oxygen. 

Molar mass of glucose is 180 g/mol (= 6 x 12 + 12 x 1 + 6 x 16) and carbon dioxide is 44 g/mol (= 12 + 2 x 16).

Hence, from stoichiometry,

1 mole of glucose requires 6 moles of carbon dioxide

or, 180 g of glucose requires 6 x 44 = 264 g carbon dioxide

or, 1 g glucose requires 264/180 g carbon dioxide

or, 332.31 g glucose requires (264/180) x 332.31 = 487.39 g carbon dioxide.

Thus, 487.39 g carbon dioxide is needed to produce 332.31 g glucose.

Hope this helps.