`||bbv|| = 8, bbu = ` Find the vector `bbv` with the given magnitude and the same direction as `bbu`.

The magnitude of a vector` u = a*i + b*j,` such that:

`|u| = sqrt(a^2+b^2)`

Since the problem provides the magnitude `|v| = 8` , yields:

`8= sqrt(a^2+b^2)`

The direction angle of the vector can be found using the formula, such that:

`tan theta = b/a`

Since the problem provides the information that the direction angle of the vector v coincides to the direction angle of vector u, yields:

`tan theta= 3/3 => tan theta = 1 =>b/a = 1 => a = b`

Replacing  a for b in equation `8 = sqrt(a^2+b^2)` yields:

`8 = sqrt(a^2+a^2)=> 8 = +-a*sqrt 2 => a = +-4sqrt2`

`b = +-4sqrt2`

Hence, the component form of the vector v can be `<4sqrt2,4sqrt2>` or `<-4sqrt2,-4sqrt2>.`