Friday, August 15, 2008

`u = , v = ` Find the projection of u onto v. Then write u as the sum of the two orthogonal vectors, one of which is `proj_v u`.

You need to evaluate the projection of vector u onto vector v using the formula, such that:


`proj_v (u) = ((u*v)/(|v|^2))*v`


You need to evaluate the product of vectors `u = u_x*i + u_y*j and v = v_x*i + v_y*j` , such that:


`u*v = u_x* v_x + u_y* v_y`


`u*v = 0*2+ 3* (15)`


`u*v = 0 + 45`


`u*v = 45`


You need to evaluate the magnitude of the vector v, such that:


`|v| = sqrt(2^2+15^2) => |v|^2 = 4 + 225 = 229`


`proj_v (u) = (45/229)*v => proj_v (u) = (45/229)*<2,15>`


`proj_v (u) = <90/229,675/229> `


Hence, evaluating the projection of vector u onto vector v yields `proj_v (u) = <90/229,675/229>` .

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