`C = 95.20^@, a = 35, c = 50` Use the law of sines to solve the triangle. (Find missing sides/angles) Round answers to 2 decimal places.

Given: `C=95.20^@, a=35, c=50`

Law of Sines  `a/sin(A)=b/sin(B)=c/sin(C)`

`35/sin(A)=b/sin(B)=50/sin(95.20)`

`35/sin(A)=50/sin(95.20)`

`sin(A)=[35sin(95.20)]/50`

`sin(A)=.6971`

`A=arcsin(.6971)`

`A=44.20^@`

`B=180-95.20-44.20`

`B=40.60^@`

`b/sin(40.60)=50/sin(95.20)`

`b=[50sin(40.60)]/sin(95.20)`

`b=32.67`